Pakai cara ya makasi

2x^2 -3x - 5 = 0
a + b = - -3/2 = 3/2
a.b = -5/2
misal PK baru akar2nya p dan q dengan p = (2 + 1/a) dan q. = (2+1/b)
p + q = (2 + 1/a)+(2 + 1/b)
= 4 + 1/a + 1/b
= 4 + { (a+b)/(ab)
= 4 + { (3/2)/(-5/2)
= 4 + -3/5
= 4 - 3/5
= 17/5
p.q = (2+1/a)×(2+1/b)
= 4 + 2/b + 2/a + 1/ab
= 4 + 2(a+b)/(ab) + 1/ab
= 4 + 2{ (3/2)/(-5/2)+ 1/(-5/2)
= 4 -6/5 - 2/5
= 4 -8/5
= 12/5
Maka PK dimaksud adalah
x^2 -17/5x + 12/5 = 0
5x^2 -17x +12 = 0