Matematika

Pertanyaan

3 kemeja dan 2 celana panjang dijual seharga rp330.000 5 kemeja dan 4 celana panjang dijual Rp Rp600.000 harga 4 kemeja dan 3 celana panjang adalah

2 Jawaban

  • kemeja = k
    celana = c

    3k+2c=330000|*2| 6k = 660000
    5k+4c=600000|*1 | 5k = 600000
    6k-5k = 660000-600000
    k = 60000

    3k+2c = 330000 ==》 3(60000)+2c =330000
    2c = 330000-180000
    c = 150000/2
    c = 75000

    4k+3c = 4(60000)+3(75000)
    = 240000+225000
    = 465000
  • ☆3 k + 2 cp = 330.000 || × 4 ||
    5 k + 4 cp = 600.000 || × 2 ||


    12k + 8cp = 1.320.000
    10k + 8cp = 1.200.000

    Dikurang

    2k = 120.000
    K = 60.000

    ☆3k + 2 cp = 330.000
    3 (60.000) + 2 cp = 330.000
    2cp = 150.000
    Cp = 75.000


    ☆ 4k + 3 cp = 4 (60.000) + 3 ( 75.000)
    =465.000

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