matematika...................................

[tex]\sqrt{3 {u}^{2} -u - 4} = \sqrt{2 {u}^{2} + 2u } \\ {( \sqrt{3{u}^{2} - u - 4) } }^{2} = {( \sqrt{2 {u}^{2} + 2u) } }^{2} \\ 3 {u }^{2} - u - 4 = 2{u}^{2} + 2 u \\ 3 {u}^{2} - 2 {u}^{2} - u - 2u - 4 = 0 \\ {u}^{2} - 3u - 4 = 0 \\ (u - 4)(u + 1) = 0 \\ u = 4 \: \: \: \: u = - 1[/tex]
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