persamaan garis lurus melalui titik (-2,-4)dan titik(-4,3)

y-y1/y2-y1= x-x1/x2-x1
y+4/3+4 = x+2/-4+2
y+4/7 = x+2/-2
-2(y+4) = 7(x+2)
-2y-8 = 7x+14
7x+2y +22 =0