^(x-3)log(x²-6x+8)= ^(x-3)log(2x-7)
Matematika
indahwidyaloka27
Pertanyaan
^(x-3)log(x²-6x+8)= ^(x-3)log(2x-7)
1 Jawaban
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1. Jawaban ahreumlim
^(x-3)log(x²-6x+8)= ^(x-3)log(2x-7)
karena basisnya sudah sama, jadi tinggal
x² - 6x + 8 = 2x - 7
x² - 6x - 2x + 8 + 7 = 0
x² - 8x + 15 = 0
(x - 3)(x - 5) = 0
x = 3 atau x = 5
HP : {3 , 5}