Diketahui fungsi g(x) = ax^+b. Jika g(2) = -1 g(-4)= 5, njlai g(-1) + 2 =

g(2)=2a + b >> 2a + b = -1
g(-4)=-4a +b >> -4a + b = 5
dieliminasi 6a = -6 >> a = -1
2a+b= -1
-2 + b = -1
b = -1 + 2 = 1
g(x) = ax + b = -x + 1

g(-1) = -(-1) + 1 = 1 + 1 = 2
jadi g(-1) + 2 = 2 + 2 = 4