Diketahui fungsi g(x) = ax^+b. Jika g(2) = -1 g(-4)= 5, nilai g(-1) + 2 =

g(-2) = -1
g(-4) = 5
g(x) = ax² + b

g(-2) = a(-2)² +b = 4a +b
g(-4) = a(-4) ² +b = 16a + b

4a+b = -1
16a +b = 5
_________-
-12a = -6
a= ½

sub. a= ½ ke 4a + b = -1
4(½) + b = -1
b = -1 -9/2
b = - 2/2 - 9/2
b = -11/2
g(x) = ½x² -11/2
g(-1) +2 = ½(-1)² - 11/2
g(-1) +2 = ½ -11/2 -4/2
g(-1) +2 = -14/2
g(-1) +2 = -7