Matematika

Pertanyaan

1/a-1/b per 1/b^2-1/a^2=......
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2 Jawaban

  • jawab


    (1/a - 1/b) / (1/b² - 1/a²) =  ...}kalikan  (a²b²)/(a²b²)
    = (1/a - 1/b) / (1/b² - 1/a²) (a²b²)/(a²b²)
    = a²b²(1/a - 1/b) / a²b² (1/b² - 1/a²)
    = (ab² - a²b) / ( a² - b²)
    = -ab(a - b) / (a- b)(a + b)
    = -ab/(a+b)
  • Aljabar.

    Harap lihat jawaban dari situs web jika kode Latexnya tidak terbaca!!!
    [tex]\displaystyle \frac{\frac{1}{a}-\frac{1}{b}}{\frac{1}{b^2}-\frac{1}{a^2}}\\ =\frac{\frac{b-a}{ab}}{\frac{a^2-b^2}{a^2b^2}}\\ =\frac{b-a}{ab}~\frac{a^2b^2}{a^2-b^2}\\ =\frac{ab(b-a)}{(a+b)(a-b)}\\ =\frac{ab(b-a)}{-(a+b)(b-a)}\\ =-\frac{ab}{b+a}[/tex]

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