hitunglah x jika : a. ²log ²log x = 2 b. pangkat 9 log (³log x ) = 0 c. ³log [³log(³log x )] = 1 d. pangkat x log (1-³log 1/27) = 2 tolong dijawab dengan benar

[tex]^2log ^2log x = 2 \\ ^2log ^2log x = ^2log {2}^{2} \\^2log x = 4 \\ ^2log x = ^2log {2}^{4} \\ x = {2}^{4} \\ x = 16 \\ \\
^9log (^3log x ) = 0 \\ ^9log (^3log x ) =^9log1 \\ ^3log x = 1 \\ x= {3}^{1} = 3 \\ \\
^3log [^3log(^3log x )] = 1 \\^3log [^3log(^3log x )] = ^3log3 \\ ^3log(^3log x ) = 3 \\ ^3log(^3log x ) =^3log {3}^{3} \\ ^3log x = 27 \\ x = {3}^{27} \\ \\
^xlog (1-^3log \frac{1}{27}) = 2 \\ ^xlog (1-^3log \frac{1}{27}) =^xlog {x}^{2} \\ 1-^3log \frac{1}{27} = {x}^{2} \\ -^3log \frac{1}{27} = {x}^{2} - 1 \\ - ^3log {3}^{ - 3} = {x}^{2} - 1 \\ 3 = {x}^{2} - 1 \\ {x }^{2} - 4 = 0 \\ (x - 2)(x + 2) = 0 \\ x = 2 \: atau \: x = - 2[/tex]