Tolong bantu yah ^,^

m=3 kg
c=2100 J/kg°C
L=336000 J/kg
∆T=0-(-10)=10°C

QA-B-C..?

Proses A-B (perubahan suhu)
QAB=mc∆T
QAB=3×2100×10
QAB=63000 J

Proses B-C (perubahan wujud)
QBC=mL
QBC=3×336000
QBC=1008000 J

QABC=63000+1008000
QABC=1071000 J
QABC=1071 kJ

Silakan dicek lagi.