Matematika

Pertanyaan

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1 Jawaban

  • 2log 16 = 2log 2^4 = 4
    3log 27 = 3log 3^3 ,= 3
    2log 8 -4log 6 + 4log 24
    2log 2^3 +4log 24-4log 6
    3 + 4log (24/6)
    3 + 4log 4
    3 + 1
    = 4
    4) log 2 = a, log 3 = b
    log 108 = log (27×4)
    = log 27 + log 4
    = log 3^3 + log 2^2
    = 3. log 3 + 2. log 2
    = 3.b + 2.a
    = 2a + 3b