Tentukan persamaan garis yang tegak lurus 2y + 2 = -7/4 (x-7) dan melalui titik (-2,-3)

2y+2=-7/4(x-7)      (-2,-3)
2y=-7/4 x +49/4 - 2
2y = -7/4 x  + 41/4
y = -7/8 x + 41/8

m1= -7/8

tegak lurus, maka:
m1 . m2 = -1
-7/8 . m2 = -1
m2 = -1 : -7/8
m2 = 8/7

y-y1=m(x-x1)
y-(-3)=8/7(x-(-2))
y+3=8/7 x + 16/7
y= 8/7 x + 16/7 - 3
y = 8/7 x -5/7
7y=8x-5