b sama c caranya gimana

b) 5^(x² - 2x) = 1/5
5^(x² - 2x) = 5^(-1)
x² - 2x = -1
x² - 2x + 1 = 0
(x - 1) (x - 1) = 0
x = 1    x = 1

c) 3^(3(2x - 3)) = 3^(5/2)
3^(6x - 9) = 3^(5/2)
6x - 9 = 5/2
2(6x - 9) = 5
12x - 18 = 5
12x = 5 + 18
12x = 23
x = 23/12