Diketahui (gof) (x) =4x²+4x dan g(x) = x²-1.tentukan nilai f(x-2)!

Misal f(x) = ax + b maka
g o f (x) = (ax + b)^2 - 1 = 4x^2 + 4x
a^2 x^2 + 2 ab x + b^2 -1 = 4x^2 + 4x
Dengan demikian
a^2 x^2 = 4 x^2
a^2 = 4
a = akar 4
a= 2

2 a b x = 4x
2. 2. b = 4
4b = 4
b = 4 : 4
b = 1

maka f (x) = ax + b = 2x + 1
jadi f (x-2) = 2. (x-2) + 1
f (x-2) = 2x - 4 + 1
f (x-2) = 2x - 3

jawab
g(x)=  x² -1
gof(x)= 4x² + 4x
g {f(x)} = 4x² + 4x
f²(x)  - 1 = 4x² + 4x
f²(x)= 4x²+ 4x + 1 = (2x +1)²
f(x)= 2x + 1
f(x-2) = 2(x -2) + 1
f(x-2)= 2x - 3