Matematika

Pertanyaan

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tolong please pake caranya

1 Jawaban

  • 1) 7a = 7 × a
    3ab = 3 × a × b
    kpk = 3 × 7 × a × b = 21ab
    fpb = a

    2) 25p³q = 5² × p³ × q
    35pq²r = 5 × 7 × p × q² × r
    kpk = 5² × 7 × p³ × q² × r = 175p³q²r
    fpb = 5 × p × q = 5pq

    3) 18a²b⁴ = 2 × 3² × a² × b⁴
    30ab²c = 2 × 3 × 5 × a × b² × c
    kpk = 2 × 3² × 5 × a² × b⁴ × c = 90a²b⁴c
    fpb = 2 × 3 × a × b² = 6ab²

    4) 21p³q²r = 3 × 7 × p³ × q² × r
    42pq³r² = 2 × 3 × 7 × p × q³ × r²
    kpk = 2 × 3 × 7 × p³ × q³ × r² = 42p³q³r²
    fpb = 3 × 7 × p × q² × r = 21pq²r

    5) 12ab² = 2² × 3 × a × b²
    20a²b³c = 2² × 5 × a² × b³ × c
    kpk = 2² × 3 × 5 × a² × b³ × c = 60a²b³c
    fpb = 2² × a × b² = 4ab²

    6) 6xy = 2 × 3 × x × y
    24x²yz = 2³ × 3 × x² × y × z
    kpk = 2³ × 3 × x² × y × z = 24x²yz
    fpb = 2 × 3 × x × y = 6xy

    7) 4a²b = 2² × a² × b
    9ab²c² = 3² × a × b² × c²
    kpk = 2² × 3² × a² × b² × c² = 36a²b²c²
    fpb = a × b = ab

    8) 12ab = 2² × 3 × a × b
    6b²c = 2 × 3 × b² × c
    15a²bc² = 3 × 5 × a² × b × c²
    kpk = 2² × 3 × 5 × a² × b² × c² = 60a²b²c²
    fpb = 3 × b = 3b

    9) 4pq²r = 2² × p × q² × r
    10pqr = 2 × 5 × p × q × r
    kpk = 2² × 5 × p × q² × r = 20pq²r
    fpb = 2 × p × q × r = 2pqr

    10) 8x²y = 2³ × x² × y
    12xy² = 2² × x × y²
    15xyz = 3 × 5 × x × y × z
    kpk = 2³ × 3 × 5 × x² × y² × z = 120x²y²z
    fpb = x × y = xy