3 3 ____ + ___ ? x+1 x-1

[tex] \frac{3}{x + 1} + \frac{3}{x - 1} \\ = \frac{3(x - 1) + 3(x + 1)}{ {x}^{2} - 1 } \\ = \frac{3x - 3 + 3x + 3}{{x}^{2} - 1 } \\ = \frac{6x}{{x}^{2} - 1} [/tex]