√8 per √3 + √2 tolong yang djawab pakek caranya!!!

[tex] \frac{ \sqrt{8}}{( \sqrt{3} +\sqrt{2} )} . \frac{( \sqrt{3} -\sqrt{2} )}{( \sqrt{3} -\sqrt{2} )} = \sqrt{8} \frac{( \sqrt{3} -\sqrt{2} )}{( \sqrt{3}^{2} -\sqrt{2}^2 )} = \sqrt{8}(\sqrt{3}-\sqrt{2}) = \sqrt{24}-\sqrt{16} \\ = 2\sqrt{6}-4[/tex]