2/(x+3) - 3/(x-2) = ?

[tex] \frac{2}{(x+3)} - \frac{3}{(x-2)} = \frac{2(x-2)}{(x+3)(x-2)} - \frac{3(x+3)}{(x+3)(x-2)} \\ = \frac{2x-4-3x-9}{(x+3)(x-2)}= \frac{-x-13}{x^{2} +x-6} [/tex]