Koordinat bayangan titik P (2,-3) oleh rotasi R[O,90°] adalah . . . pakai cara ya

jawab

P(x,y)=(2, -3)
rotasi [O, 90°]


[tex] \left[\begin{array}{ccc}x'\\y'\end{array}\right]\,= \left[\begin{array}{ccc}cos 90&-sin 90\\sin 90&cos 90\end{array}\right] \left[\begin{array}{ccc}2\\-3\end{array}\right] \\ \left[\begin{array}{ccc}x'\\y'\end{array}\right]\,= \left[\begin{array}{ccc}0&-1\\1&0\end{array}\right] \left[\begin{array}{ccc}2\\-3\end{array}\right]\,= \left[\begin{array}{ccc}3\\2\end{array}\right] \\ [/tex]

P(2,-3) R{O,90°] →P'(3,2)