Jika f(2x+a)=3x+4a Dan f(a)=2,makq f(1)=…

f(2x + a) = 3x + 4a
misalkan y = 2x + a
               x = (y - a)/2
f(y) = 3[y - a]/2 + 4a
f(y) = 3y/2 - 3a/2 + 8a/2
f(y) = 3y/2 + 5a/2

f(a) = 2
3a/2 + 5a/2 = 2
8a/2 = 2
8a = 4
a = 4/8
a = 1/2

jadi f(y) = 3y/2 + 5/4
f(1) = 3/2 + 5/4
f(1) = 6/4 + 5/4
f(1) = 11/4