tolong dijawab soal no 3 dari a sampai d , kalau bisa saya kasih poin 20,pake caranya y

a. 24m = 12
→ m = 12/24 = 1/2 =0,5

b. 3z + 11 = -28
→ 3z = -28 - 11
→ 3z = 39
→ z = 39/3 = 13

c. 25 - 4y = 6y + 15
→ 25 - 15 = 6y + 4y
→ 10 = 10y
→ y = 10/10 = 1

d. 1/3 (x-2) = 2/3x - 13/3
→ x/3 - 1/3 = 2/3x - 13/3 (dikali 3)
→ x - 1 = 2x - 13
→ x - 2x = -13 + 1
→ -x = -12
→ x = 12