dua muatan listrik masing masing 9 dan -12 mikro terpisah sejauh 30 cm . berapa gaya tersebut

mikroC = 10^-6C
cm = 10^-2m
^ = pangkat

F = k x (q1.q2)/r^2
= 9.10^9 x (9.10^-6 x 12.10^-6)/(30.10^-2)^2
= 9.10^9 x (1,08.10^-10)/9.10^-2
= 1,08.10^1
= 10,8N

I did my best