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Hambatan diatas memiliki susunan paralel, kita cari dgn rumus paralel
1/Rp = 1/R1 + 1/R2 + 1/R3 = 1/40 + 1/20 + 1/20 = 5/40
Rp = 40/5 = 8

Sekarang cari I
V = I.R
24 = I.8
I = 24/8 = 3A

I did my best