(3×-4y+2×-7+5y+8)= (4×+3y-2y+7-5y-8)=
Matematika
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Pertanyaan
(3×-4y+2×-7+5y+8)=
(4×+3y-2y+7-5y-8)=
(4×+3y-2y+7-5y-8)=
1 Jawaban
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1. Jawaban RafidahAzzah
a. (3x-4y+2x-7+5y+8)
=3x+2x-4y+5y-7+8
=5x+y+1
b.(4x+3y-2y+7-5y-8)
=4x+3y-2y-5y+7-8
=4x-4y-1