brainly perkalian bentuk akar dari (3-2√3) (3-2√3)

[tex](a-b)^{2} = a^2-2ab+b^2 \\ (3-2 \sqrt{3}) (3-2 \sqrt{3})=(3-2 \sqrt{3})^2 \\ =3^2-2.3.2 \sqrt{3}+(2 \sqrt{3})^2 \\ = 9-12 \sqrt{3}+12 [/tex]

semoga membantu kakak ku